100 points.. ? this is my last question i have on my homework assignment. i'm unable to figure it out myself so would be highly -you!

The fromula of a distance between two points:

We have the points J(-5, 6), K(3, 4) and L(-2, 1). Substitute:

The perimeter of ΔJKL:

The area of ΔJKL:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet