Find all zeros of the equation -3x^4+27x^2+1200=0 step by step

The roots are +/- 5 and +/- 4i  or 5, -5,  4i,  -4i

Step-by-step explanation:

Begin by dividing through by - 3

-3x^4 / - 3   + 27x^2/-3   +   1200/-3 = 0

x^4 - 9x^2 - 400 = 0                   This makes it easier to work with. Substitute

z = x^2

z^2 - 9z - 400 = 0                        Factor

(z - 25)(z  + 16) =  0                       Put the x^2 back in

(x^2 - 25)(x^2 + 16)

Factor x^2 - 25 using the difference of squares.

(x^2 - 25) = (x + 5)(x - 5)

x = +5 and x = - 5

Factor x^2 + 16

x^2 + 16 = 0

x^2 = - 16                Take the square root of x^2 and -16

x = sqrt(-16)

x = +4i, x = - 4i

Answer

The roots are +/- 5 and +/- 4i

now, as far as x² + 16 = 0 root, well

which is another way of saying, there's no solution coming from that factor, or one can also say, there are two complex solutions.

its d. the first coordintaes are 10,32

step-by-step explanation: