Number 17 and you . i don’t understand it . do you plug in each 10-50 as t into your calculator?

The half-life for such a substance is the time required to have the amount (in grams ) at time (in seconds ), , decay to half the starting amount . In other words, for krypton-91, after 10 seconds we would have . We can use this information to solve for , then plug in various values of to find the amount of krypton-91 that's left...

But we don't need to! We already know it takes 10 seconds for half of the substance to decay. So if we start with 16 grams, then after 10 seconds, 8 grams will remain.

10s later (after a total of 20 seconds), 4g will remain.

10s later (30s), 2g will remain.

10s later (40s), 1g will remain.

10s later (50s), 1/2 g will remain.

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)