What is the general form of the equation of the line shown? y - 2 = 0 y + 2 = 0 x - 2 = 0

Option A is correct.

General form of the equation of the line:  y-2 = 0

Step-by-step explanation:

The general form of the equation is given by:

y = mx +b where m is the slope and b is the y-intercept.

y-intercepts of the line is the value of y at the point where the line crosses the y-axis(i.e x= 0)

From the given figure;

we can see that the line crosses the y-axis at y =2  and also here the slope is , m= 0

therefore, by definition of y-intercepts

y-intercept (b) = 2

Therefore, the equation of line as shoen in figure is:

y = (0)x + 2

or

y = 2

y-2 = 0

Therefore, the general form of the equation line as shown in the figure is:

y-2 =0

y-2=0 is the correct answer. thanks

Step-by-step explanation:

step-by-step explanation:

divide, then simplify your answer.

1. make -15.66 ÷   5.8 a fraction. then divide.

2. simplify.  

3. final answer.  

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true