Graham received 1 penny on the first day of the month, and each day after that he received triple the number of pennies that he received the day before. on what day of the month did graham first receive over 3 million dollars on a single day?

Step-by-step explanation:

Graham received i penny on the first day of the month, and each day after that he received triple the number of pennies.

The sequence formed for each day pennies received will be

1, 3, 3², 3³................... n terms

Since explicit formula of a geometric series is represented by

Here a = first term of the sequence = 1

r = common ratio of the sequence = 3

Now we have to calculate on which day Graham will receive 3 million dollar

So we have to find the nth term of this sequence which is equal to $3000000

Now we put these values in the explicit formula

Taking log on both the sides

log(3000000) =

6.4771 = (n - 1)log3

6.4771 = (n - 1)(0.4771)

(n -1) =

n = 13.57 + 1

n = 14.57

Therefore, on 15 the day he will get over 3 million dollars.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

12 cups   is the answer

step-by-step explanation: