Am is a median in △abc (m∈ bc ). a line drawn through point m intersects ab at its midpoint p. find areas of △apc and △pmc, if area of apm=35m^2.

Area of ΔAPC = 70 square meter and Area of △PMC= 35 square meter

Step-by-step explanation:

Here, AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P.

Since, we know that median divides a triangle into equal areas.

Therefore, By the diagram we can say that If Area of ΔAPM=35 .

Therefore Area of ΔBPM = 35 ( Because MP is the median of triangle MAB.)

⇒ Area of ΔPMC = 35 ( Because MP is the median of triangle PBC.)

Now, Area of ΔAPC= Area of ΔPBC ( CP is the median of ΔABC)

But area of ΔPBC= Area of ΔBPM+ area of ΔPMC= 35+35=70 square unit.

⇒ Area of  Δ APC= 70 square unit.

a 4/6 = 9/12   not proportional

step-by-step explanation:

to find which are not proportional, we can use cross products

if it is true, they are proportional.   if it is not true, they are not proportional.

a 4/6 = 9/12

4* 12 = 6*9

48 = 54

not this is not proportional  

b 2/3 = 12/18  

2* 18 = 3 * 12

36 = 36

this is proportional

c 5/4 = 10/8  

5*8 = 4*10

40 = 40

this is proportional

d 7/5 = 35/25

7*25 = 5 * 35

175 = 175

is proportional