Given: bisects ∠bac; ab = ac which congruence theorem can be used to prove △abr ≅ △acr? a. aas b. sss c. asa d. sas

SAS

Step-by-step explanation:

Here ABC is a triangle, In which angle BAC is bisected by line AR where, .

Thus in triangles ABR and ACR,

AB= AC ( given)

Therefore

( by the property of angle bisector)

And,       (reflexive)

Thus by SAS postulate,

△ABR ≅ △ACR.

Therefore, Option D is correct.

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x