For the following system of equations, what is the x-value of the solution? -x+2y=6 6y=x+18 a-) -18 b-) 0 c-) -6 d-) 3

-x + 2y = 6

6y = x + 18

Let's rewrite these equations.

-x + 2y = 6

6y - x = 18

If we multiply the second equation by -1 we can add both of them.

-x + 2y = 6

-6y + x = -18

Add:

-x + (-6y) + 2y + x = 6 + (-18)

2y - 6y + x - x = 6 - 18

-4y = -12

y = -12/-4

y = 3

Substitute y in the equation:

-x + 2y = 6

-x + 2.3 = 6

-x + 6 = 6

-x = 6 - 6

-x = 0

x = 0

Option B.

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube