At the movie theatre, child admission is$5.30 and adult admission is$9.50. on tuesday, 165 tickets were sold for a total of $1265.10. how many child tickets were sold that day?

let a be the adult tickets and c be the child ticket.

1st equation: a + c = 165

2nd equation: 9.50a+ 5.30c = 1265.10

Solve the 1st equation for a:

a + c = 165

a = 165 -c

Substitute a value from 1st equation to 2nd equation:

9.50a + 5.30c = 1265.10

9.50(165 - c) + 5.30c = 1265.10

1567.5 - 9.5c + 5.30c = 1265.10

1567.5 - 1265.1 = 4.2c

302.4 = 4.2c

302.4/4.2 = c

72 = c

There were 72 child ticket sold.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

the answer is 2/54

step-by-step explanation: