For what values of h does the equation have real solutions. √(3x-h)= x+3

Square both side to get

3x-h = (x+3)^2

distribute the squared

3x - h = x^2 + 6x + 9

subtract 3x from both sides

-h = x^2 + 3x + 9

The answer will only have real solutions if the right side is factorable

h= -19, and 2.25 are both values that would make the right side factorable

answer: b.

step-by-step explanation:

the y coordinate for point b is 0, and answer b is the only one with that y coordinate.

where r the answers

step-by-step explanation: