Arectangle has a length of 15 inches less than 5 times it’s width. if the area of the rectangle is 2750 square inches. what is the length of the rectangle

let L = length and let W = width.

Use the equations 2L + 2W = 2750

and L = 5W + 15

Then do the steps as follows -

1. Plug the equation for what L equals into the first equation

2(5W+15) + 2W = 2750

2. Then distribute the 2

10W + 30 + 2W = 2750

3. Then add like terms

12W + 30 = 2750

4. Then subtract 30 from both sides

12W = 2720

5. Divide by 12 on both sides

W = 226.67

6. Then plug that into the second equation

L = 5(226.67) + 15

L = 1148.35 should be the answer

inequality:

620-37.4p ≥ 450

the minimum amount of packages needed to be removed from the elevator is 5.

step-by-step explanation:

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step-by-step explanation:

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