Fiona is choosing flower bouquets for her wedding. the probability that a bouquet has roses is 0.98, has orchids is 0.87, or has daisies is 0.94. what is the probability that a bouquet has roses or daisies if the probability that a bouquet has roses and daisies is 0.97? a) 0.92 b) 0.95 c) 0.97 d) 0.98

0.95

Step-by-step explanation:

Given that in a bouquet of flowers

Probability of Roses = P (R) = 0.98

Probability of Orchids = P (O) = 0.87

Probability of Daisies = P (D) = 0.94

Probability of Roses and Daisies = P (R ∩ D) = 0.97

Note: In probability, the AND operation is represented by intersection symbol (∩) and OR operation is is represented by union symbol (U).

Now we have to find the probability of roses or daisies in a given bouquet of flowers. In order to calculate it we use the following formula:

Probability of roses or daisies = P (R U D) = P(R) + P (D) - P(R ∩ D)

P (R U D) = 0.98 +0.94 - 0.97

P (R U D) = 0.95

So, the probability of getting roses or daisies in a bouquet of flowers is 0.95 or 95 percent.

6 (3) - 4 + 32

hope this

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.