Solve 2a-b+c= -5 a - b+c= -5 by subsittution 2a + b =5a. a= -2,b=0,c = -2b. a= -2,b=0,c = -1c. a= 1,b = 3,c= -6d. a= 1,b = 3,c = -4

Please find the explanation below

Step-by-step explanation:

2a-b+c= -5 (A)

a-b+c= -5 (B)

2a+b =5 (C)

from equation A subtracting 2a from both sides we get

-b+c = -5-2a

Substituting this value in B

a-5-2a=-5

a-2a-5+5=0

-a=0

a=0

Putting this value in C

2(0)+b=5

b=5

Putting these values in B

0-5+c=-5

c=0

We do not have any option with these solutions . Hence, it seems that there is something missing from the equation.

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.