Suppose that there are two types of tickets to a show: advance and same-day. the combined cost of one advance ticket and one same-day ticket is $40. for one performance, 20 advance tickets and 30 same-day tickets were sold. the total amount paid for the tickets was $950. what was the price of each kind of ticket?

Let there be a advanced tickets and s same day tickets, Then:-

a + s = 40

20a + 30s = 950(1)

Multiply first equation by -30

-30a - 30x = -1200 (2)

Adding equations (1) and (2):-

-10a = - 250

a = -250/-10 = 25

So s = 40 - 25 = 15

-  advanced tickets cost $25 and same day cost $15.

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3