Will mark the brainiest plz ! lots of points determine how many solutions there are and if there are solutions solve for angle b. a) a=9, b=11 and a= 61 degrees b) a=25, b= 28 and a= 43 degrees.

a) no solutions

b) B = 49.8° or 130.2°

a) By the law of sines, ...

... sin(B)/b = sin(A)/a

... sin(B) = b·sin(A)/a = (11/9)·sin(61°) = 1.069 . . . . . not realizable

there is no solution

b) As before, ...

... sin(B) = (28/25)·sin(43°) ≈ 0.763838...

... B = arcsin(0.763838...) ≈ 49.80°

The side length b is longer than the side length a, so there will be two solutions. The other angle for B is the supplement to this one:

... B = 180° -49.8° = 130.2°

the reporter's right

step-by-step explanation:

1/4 = .25 / 25%

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

br

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 =   (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4   we need to find some relationship between a and b.

let's try ab = bc  

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2 

br = sqrt(3) * a

cp

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram. 

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a 

cp = sqrt(3)*a

aq

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a 

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt  3) * a which agrees with the other two.