Consider the graph of the linear function h(x) = -6 + 2/3 x. which quadrant will the graph not go through and why.

The answer is b guys

Step-by-step explanation:

There are four quadrants.

I.  x>0, y>0

II. x<0, y>0

III. x<0, y<0

IV. x>0, y<0

note that for any x<0, h(x) < 0 (that corresponds to III)

Why?

So, the graph not go through II.

Note that, if x = 3, h(3) = -4 < 0, (that corresponds to IV), and if x = 12, h(12) = 2> 0, that corresponds to I.

well my understanding of this question is they want you to use the y=14.1x -2.3 and put the coordinates they gave you onto the line segment of   y=14.1x -2.3

step-by-step explanation:

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!