Use substitution process to find x, y,and z from the equations 2x+4y+3z=14 , y+3z=11 , z=4

Work backwards.

Start with z = 4.

Now deal with the middle equation

y + 3z = 11                    Substitute z = 4 and solve for y

y + 3(4) = 11                  Subtract 12 from both sides

y + 12 = 11

y + 12 - 12 = 11 -12         Combine terms on the left and right

y = - 1                             Now use the top equation for x

z = 4                              z still = 4

2x + 4(-1) +3(4) = 14

2x - 4 + 12 = 14              Solve 3z

2x + 8 = 14                     Subtract 8

2x + 8 - 8 = 14 - 8          Combine

2x = 6                            Divide by 2

x = 6/2

x = 3

Answer

x = 3

y = - 1

z = 4  

the first option i believe

step-by-step explanation:

proportions are fractions that equal to each other. so if two fractions are the same, they are proportional.

let's check the answers to see if they are proportional.

question a is not proportional because you can't turn 1.5/3 to 3/9. if you try to multiply 1.5/3 by 2 or 3, you wont get 3/9. it's impossible to make the fractions the same.

question b is not proportional because you can't turn 22/33 to 4/6. 33 can't go into 6.

question c is proportional because when you multiply 2 and 3 by 71, you would get 142/213, and those fractions equal to each other

question d is proportional because when you divide 14 and 7 by 2, you would end up with 7/3.5, and those fractions equal to each other.