Give the excluded values for the rational equation. (3x)/(x-+3)/(x+4)=(2x+7)/(x^(2)-16)

Answer is x =-4 and x =4

Explanation:

We find that there is a common denominator.

This should not be equal to 0.

i.e. x ≠4 or x ≠-4

Thus x=4 and x=-4 are the excluded values for the rational equation.

Once we exclude these values, we cancel and equate numerator

3x(x+4)-(x+3)(x-4) = 2x+7

Simplify to get  3x^2+12x-x^2+x-12 = 2x+7

2x^2+11x-19 =0

Thus when we exclude those values, we et a quadratic equation with 2 solutions.

simplify to get

mxb67

step-by-step explanation: