Find the value of the variable such that the value of 5−a is 20 greater than the value of 6a−1

a = -2

We want (5-a) to be 20 more than (6a-1). Then we can write ...

... (5-a) = (6a-1) +20

If we add (a-19) to both sides, we get

... -14 = 7a

... -2 = a . . . . . divide by 7

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Comment on the graph

In the attached, we use the variable x, because this graphing calculator likes variables named x and y. We graph each expression and find the place where they both have the same value for the same value of x (the point of intersection). The value of the variable x at that point is -2, the solution we seek.

walter needs to make at least 5 more cookies but no more than 40. 5 ≥ x ≥ 40;

step-by-step explanation:

walter has to make a minimum of 20 cookies. he already has 15 cookies made, so he must make 5 more to meet the minimum.

the maximum amount of cookies he can make is 55. he already has 15, so he has to make no more than 40 more cookies to meet the maximum.