1substitute p=5, q=7, r = -2 a) 2q + 5r b) 3(p+6) + q + r c) 3m(8 +n) + n squared ( basicly n x n) 2 substitute m=2, n = 3, p= -5 a) m(3m+4n) b) n squared (m+p sqaured) c) 3m(8+n) + n sqaured

1.

a.) 2q + 5r

2(7) + 5(-2)

14 - 10 = 4

b.) 3(p + 6) + q + r     Plug in the numbers

3(5 + 6) + 7 - 2   Solve inside the parentheses first

3(11) + 7 - 2

33 + 5 = 38

2.

a.) m(3m + 4n)

2(3(2) + 4(3))

2(6 + 12)

2(18) = 36

b.) n²(m + p²)

(3)²(2 + (-5)²)

9(2 + 25)

9(27) = 243

c.) 3m(8 + n) + n²

3(2) (8 + 3) + 3²

6(11) + 9

66 + 9 = 75

b.my answer is b.

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