What is the average rate of change of the function on the interval from x = 0 to x = 5? f(x)=12(3)x enter your answer, as a decimal, in the box.

580.8

The average rate of change of a function f(x) between x-values x1 and x2 is given by

... average rate of change = (f(x2) -f(x1))/(x2 -x1)

For your function

... f(x) = 12·3^x

and x-values 0 and 5, this becomes ...

... average rate of change = (f(5) -f(0))/(5 -0) = (2916 -12)/5 = 580.8

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation:

12cm

the answer is d