What dimensions of the box maximize the volume of the box? you so much!

so, let's recall that the volume of a rectangular prism, namely a box, is Lwh, just the product of its dimensions, length, width and height.

now, check the 1st picture below. we know the original paperboard is a 16x14, so the width, as you see in the picture is w = 8 - x, its length is L = x, and its height is 14 -(x/2) - (x/2).

now, let's find the critical points, by setting the derivative to 0, and then we'll do a first-derivative test.

now, if we plot those two points, we get 3 regions, and then we check each of those regions to see what's the value of the first derivative.

check the 2nd picture below, that'd be the first derivative test, as you can see from the arrows, the slope increases and then decreases at 3.28, namely that critical point is the maximum, so the Volume maximizes at x = 3.28.

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl