Write an equation of the line that passes through (1,2) and is parallel to the line y=−5x+4 y=? show steps

We know that the slope is -5, so:

y = -5x + b

Input (1, 2)

2 = -5 + b

b = 7

So:

y = -5x + 7

You are using the equation:

y = mx + b

You need to find "m" and "b".

"m" is the slope, "b" is your y-intercept(when x = 0)

For the equation of the line to be parallel to the given equation, the slopes have to be the SAME. The slope of the given line is -5, so the parallel line's slope is also -5. (m = -5)

y = mx + b

y = -5x + b

To find b, you plug in the point (1,2) into the equation

y = -5x + b

2 = -5(1) + b

2 = -5 + b Add 5 on both sides to get "b" by itself

2 + 5 = -5 + b + 5

7 = b

Your equation is:

y = -5x + 7

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1