The midsegment through the legs of an isosceles triangle is 4 in. find the sides of the triangle if its perimeter is 20 in.

Given: Consider an  isosceles triangle ABC as shown below in the attachment.

Perimeter = 20 in. and the mid segment through the legs of an isosceles triangle is 4 in.  

An isosceles triangle is a triangle that has two sides of equal length.

Therefore, in triangle ABC, AB = AC = a (let)  andf BC = b (let)

Construct a line DE parallel to BC.

The Triangle Mid segment Theorem states that in a triangle, the segment joining the midpoints of any two sides will be parallel to the third side and half its length.

As we know the mid segment is 4 in. i.e, DE = 4 in.

therefore, by mid segment theorem the parallel side i.e, BC = 2 DE

then;  BC = in.

or  BC = b = 8 in.

Perimeter of an isosceles triangle is the sum of the three lengths.

I,e P = a+a+b = 2a +b ;  where P is the perimeter ,  a and b are the sides of the triangle.

Now, substituting the values of b = 8 in in the given perimeter formula to solve for a;

Subtract 8 from both sides of an equation;

2a+8-8 = 20 -8

Simplify:

2a = 12

Divide both sides by 2 we get;

Simplify:

a =6 in.

Therefore, the sides of the given triangle is; a= 6 in and b = 8 in

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )

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step-by-step explanation: