The length of a rectangle is 4 less than 3 time the width. what is the area of the rectangle?

Use the quations 2L + 2W = Area

and L = 3W -4

Plug the second equation into the first and solve for W

2(3W-4) + 2W = A

6W - 8 + 2W= A

8W - 8 = A

8W = 8

W = 1

Then plug that into the second equation

L = 3(1) -4

L = 3 -4

L = -1

Then plug both of the answers into the first equation

2(-1) + 2(1) = A

-2 + 2 = A

0 = A

That should be the answer, but since there was no given Area, i'm not sure.

I hope this helped though!

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry