Aline intersects the origin and contains the point (x, y) what is the slope of the line

The slope of this line would be y/x

Step-by-step explanation:

In order to find the slope of this line, we can use the slope formula and the two points given (0,0) and (x, y)

m(slope) = (y2 - y1)/(x2 - x1)

m = (y - 0)/(x - 0)

m = y/x

x^6

step-by-step explanation:

this is correct because:

x-6=0

0*x=0

so

x^6

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.