Asimple random sample of 50 stainless steel metal screws is obtained. the screws have a mean length of 0.73 inches. assume the population standard deviation is 0.012 inches and the confidence level is α = 0.05. find the p-value you would use to test the claim that the screws have a mean length equal to 0.75 inches as indicated on the package label. 0.9999 0.0002 1.9998 0.0001

Step-by-step explanation:

A simple random sample of 50(n) stainless steel metal screws is obtained. The screws have a mean length of 0.73(mu) inches. Assume the population standard deviation is 0.012(sigma) inches and the confidence level is α = 0.05.

Set up hypotheses as:

(two tailed test at 5% sign. level)

Mean difference =

Std error of sample =

Test statistic = Mean diff/std error

=

Since population std dev is known and also sample size >30 z test can be used.

p value <0.0001

idkit the do u know da way and ligma consumed ninja

step-by-step explanation:

i believe the answer is c.