What is the equation of the line passing through (-4,5) perpendicular to x + 2y = 5bin point slope form

The equation of the line would be y = 2x + 13

Step-by-step explanation:

To find the equation, you first need to solve for y so we can get the original slope.

x + 2y = 5

2y = -x + 5

y = -1/2x + 5/2

Now that we have the original slope of -1/2. So the perpendicular slope is 2 (perpendicular slopes are opposite and reciprocal). Now we can use that and the point in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 5 = 2(x - -4)

y - 5 = 2(x + 4)

y - 5 = 2x + 8

y = 2x + 13