When an experiment began, the temperature of a substance was −5°c . during the experiment, the temperature rose exponentially. the scientist will sketch a graph of the situation, where x represents the time after the experiment began, and y represents the temperature of the substance at that time. the scientist will only sketch the graph in the quadrant or quadrants for which it makes sense to. in which quadrant or quadrants will the scientist sketch the graph? quadrants i and iv only quadrants i, ii, iii, and iv quadrants i and ii only quadrant i only

If the temperature is rising from -5 on the x-axis, then the sketches would only appear in Quadrants II and I, as it rose higher and higher. Hope I helped!

In which quadrant or quadrants will the scientist sketch the graph?

Option I: Quadrants I and IV only

Step-by-step explanation:

x represents the time after the experiment began. The experiment began at x=0, and the time is a positive quantity, then x>=0. The x is positive in the Quadrants I and IV.

y represents the temperature of the substance at that time. When the experiment began, the temperature of the substance was −5°C (negative):

y < 0. y is negative in Quadrants III and IV

During the experiment, the temperature rose exponentially, then the temperature must increase and take positive values. y is positive in Quadrants I and II.

Like x is positive (Quadrants I and IV) and y is negative (Quadrants III and IV) and positive (Quadrants I and II), the scientist will sketch the graph in Quadrants I and IV only

im pretty sure it would be 5 am, hope that , and give brainliest and guys if this is right then press the button and give 5 stars

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1