Atriangle has two sides of length 1 and 18. what is the smallest possible whole-number length for the third side?

c must be 18

Explanation:

From the triangle inequality we know that the sum of any two sides must be larger than the third side. We us the inequality here:

a = 1, b = 18, c unknown

a + c > b -> 1 + c > 18 -> c > 17

b + c > a -> 18 + c > 1 -> c > 0

a + b > c -> 18 + 1 > c -> c < 19

The third side must be greater than 17 and smaller than 19. So the smallest possible (and the only possible) whole-number length for c is 18

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752