Which is the solution set to the inequality (4x-3)(2x-1)& gt=0?

(4x - 3)(2x - 1) ≥ 0

First, find the zeros:

4x - 3 = 0         2x - 1 = 0

x =               x =

Next, plot these points and choose test points on the outside and between the zeros:

←-------0------------------------1------→

Lastly, plug in the test points and look for a positive result (since it is greater than 0).

Test Point 0: [4(0) - 3][2(0) - 1]  = ( - )( - ) = +  THIS WORKS!

Test Point : [4() - 3][2() - 1]  = ( - )( + ) = -  This does NOT work

Test Point 1: [4(1) - 3][2(1) - 1]  = ( + )( + ) = +  THIS WORKS!

x ≤   or   x ≥

Interval Notation: (-∞, ] U [, ∞)

Graph: ←------          --------→

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

the diver is 33 feet below the surface.

step-by-step explanation:

hope this