In quadrilateral abcd, aabd: aacd=1: 2. if bh is an altitude in △abd and cl is an altitude in △acd, find bh: cl.

Answer

BH:CL. = 1:2

Explanation

It is given that,a quadrilateral ABCD, area of triangle ABD: area of triangle ACD=1:2.

Let BH is an altitude in △ABD and  CL is an altitude in △ACD,

In these two triangle Ad be the base  

Area of △ABD= 1/2 x AD x B

Area of △ACD  = 1/2 x AD x CL

We know that Area of △ABD /Area of △ACD  1/2

[1/2 x AD x BH] /[1/2 x AD x CL] = 1/ 2

BH/CL = 1/2

BH : CL = 1:2

An example figure is attached with this answer.

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0