Two particles start at the point (1,0) on a unit circle and move in opposite directions. the particle moving counter-clockwise is traveling with velocity 3 degree/sec. the particle moving clockwise is traveling with velocity 42 degree/sec. what is the angle corresponding to the point at which the particles will meet?

Let the number of degrees that the counterclockwise particles moves through be d degrees.

The number of degrees that the clockwise particle moves through will be 360-d degrees:.  The times taken to where they meet is the same for both particles.

Rate = degrees / time , so:-

3 = d/ t ;  giving   t = d/3

42 = 360- d / t so t  = (360 - d) / 42

Equating values of t:-

d/3 = (360-d) / 42

42d =  1080 - 3d

d = 1080 / 45

=  24 degrees  (answer)

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)