Suppose you bought eight oranges and on grapefruit for a total of $4.60. later that day, you bought six oranges and three grapefruits for a total of $4.80. now you want to find the price of each orange and of each grapefruit. write an equation for each purchase. solve the system of equations. use process of elimination. show all your work!

8*  oranges + 1 graperfuit = 4.60

6* oranges + 3 grapefruit = 4.80

multiply the first equation by 3

24 oranges + 3 grapefruit = 13.8

subtract the 2nd equation

24 oranges + 3 grapefruit = 13.8

-6* oranges + 3 grapefruit = 4.80

18 oranges = 9

oranges = .50

6 oranges + 3 grapefruit = 4.80

6 * .5 + 3 grapefruit = 4.80

3 + 3 grapefruit = 4.80

subtract 3 from each side

3 grapefruit = 1.80

grapefruit = .60

oranges  $ .50

grapefruit = $.60

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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