When you are given one quadratic equation and one linear equation what do you do to solve it algebraically to find the solutions rather than graphing it. example in the picture

both equation having y on the left side

So we can equate the right side of the equation

Subtract 4x on both sides

Add 5 on both sides

Now we solve for x

Divide the whole equation by 2

(x-2)(x-2)=0

(x-2)^2 =0

So x= 2

Now we find out y when x=2

y=4x-5

y= 4(2) -5

y = 8 -5 = 3

So solution is x=2  and y = 3

(2,3)

answer: 370

step-by-step explanation:

remember use pemdas! there are no parentheses or exponents so lets move onto the first part of the equation: multiplication and division. first, lets break the first part of the equation up into something easier using the distributive property. 28 * 12= (20 *12) + (8*12) you know that 20*12 is 240 and 8*12 is 96. add them and you get 336. then, lets solve the last part of the equation (the last part of pemdas is addition and subtraction). 336 plus 34 is 370. hope this !

180

step-by-step explanation: