M∠gah = 62° m∠adb = 148° find the m∠afd.

We are given : m∠GAH = 62° m∠ADB = 148°.

We need to find : m∠AFD.

m∠GAH = 62° = m<FAD                : Vertical angles.

m∠ADB + m<ADF = 180°               : Linear pair angles.

Substituting m∠ADB = 148°

148° + m<ADF = 180°

Subtracting 148 from both sides, we get

148°-148 + m<ADF = 180°-148

m<ADF = 32°

Now,

Sum of all angles of a triangle is =180°.

Therefore,

m<FAD + m<ADF + m∠AFD = 180°.

Substituting m<FAD = 62° and  m<ADF = 32°, we get

62+32 + m∠AFD = 180°.

94 + m∠AFD = 180°

Subtracting 94 from both sides, we get

94-94 + m∠AFD = 180°-94

m∠AFD = 86°.

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3