Aline passes through the point (10,-1) and has a slope of -1/2

Hi there!

I'm guessing you want to know what the equation of the slope-intercept line is.

The general equation for the slope-intercept line looks like this:

y = mx + b

Where "m" is the slope and "b" is the y-intercept.

Since we know what the slope is and we have the coordinates of a point, you can replace the slope and the value of the coordinates "x" & "y" in the equation and solve for "b" in order to find the whole equation :

y = mx + b

-1 = -1/2(10) + b

subtract "b" from each side of the equation

-1 - b = -1/2(10)

Add 1 to each side of the equation

-b = -1/2(10) + 1

-b = -5 + 1

-b = -4

Divide each side of the equation by -1

b = 4

Since you now know the value of "b" you can go ahead and write the slope-intercept equation with the slope in it and the y-intercept value also (b) :

y = -1/2 + 4

There you go! I really hope this helped, if there's anything just let me know! :)

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