The length of a rectangle is 3 more than the width. if the area is 40 square inches, what are the dimensions.

Need ! give step by step solutions on how to solve number one [tex]\frac{9-2\sqrt{3} }{12+\sqrt{3} }[/tex] number two [tex]x+4=\sqrt{13x-20}[/tex] number three (domain and range) [tex]f(x)=2\sqrt[3]{x} +1[/tex]

What term makes it inconsistent y=2x - 4

Factor and solve to find roots x squared -x - 90 =0