Mathematics, 03.07.2019 02:30 garrettbridges6435

Create an equation that represents a line that is perpendicular to a line with a slope -2?

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Answer from: jsushehdhdu

(first step:

you must remember the following theorem :

Two lines whose slopes are m1 and m2, are perpendicular if and only if m1m2 = -1

(second step

you have one slope given and it is -2 then you substitute in the previous equation

(third step

m1*-2=-1⇒m1=-1/-2⇒m1= 1/2

it means that new slope of the equation is 1/2

(for step

with a given point and a the slope you can build the equation that is perpendicular to a line with slope -2

the equation point- slope is

y-y1=m(x-x1)

with any given point as (2,-5) substitute it in the previous equation

[y-(-5)]= 1/2(x-2)⇒ (y+5) = 1/2x-1/4⇒y-1/2x+5+1/4⇒y-1/2x+21/4 =0

(five step

you must look for the value of x in the following equation

y-1/2x+21/4 =0

where, y = 1/2X-21/4 and this is the equation that represents a line that is perpendicular to a line with slope -2

Answer from: Quest

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

Answer from: Quest

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

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