The straight line l passes through (a,4) and (3a,3). find the values of a and c if l has equation x + 6y + c =0

The equation of a straight line is represented as: .

The values of a and c that makes a straight line are 3 and -27 respectively.

The points are given as:

The equation of the line is:

Substitute for x and y in

Substitute for x and y in

So, we have:

Subtract both equations

Solve for a

Divide by -2

Substitute in

Solve for c

Hence, the values of a and c are 3 and -27 respectively.

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let's firstly put x + 6y + c = 0, in slope-intercept form, to see what's its slope is.

so, now we know that the line L has a slope of -1/6, therefore then

so, since now we know a = 3, that means the points of L are (3,4) and (9,3), so let's find its equation.

if you're wondering why we multiplied by the LCD of 6, is just to do away with the denominators.

10 down (bang1)

5 up

5down (2)

2.5 up

2.5 down (3)

1.25 up

1.25 down (4)

now add them up : )

hoped i lol

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step-by-step explanation: