If the point (-1/2, y ) lies on the line whose equation is 2 x - 3 y = 6, what is the value of y ? -7/3 -5/3 7/3

Hi there!

In order to find the value of "y" when "x" is equal to -1/2, you need to replace the "x" in your equation with it's value (which is -1/2) and then solve the equation by isolating "y" :

2 (-1/2) - 3y = 6

Add 3y to each side of the equation

2(-1/2) = 6 + 3y

Subtract 6 from each side of the equation

2(-1/2) - 6 = 3y

-1 - 6 = 3y

-7 = 3y

Divide each side of the equation by 3

-7/3 = y

There you go! I really hope this helped, if there's anything just let me know! :)

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: