Solve the system by substitution 5x+3y=8 3x+y=8

First you'd have to eliminate one of the variables, so which I used y. So to get rid of y, you need to multiply the whole equation, 3x+y=8, by 3. Which then you get 9x+3y=24.

On the second equation, it's stays the same. 5x+3y=8, except you chane the value of the number, so if it's positive change it to negative and vice versa.

So now you have -5x-3y=-8 and 9x+3y=24.

9x + 3y =24

-5x - 3y = 8

if you combine the terms, you'll see y is removed from the equation 3y-3y=0.

You're left with 4x=16, which x is 4.

Now you can substitute 4 for x to find y. Just use one of the equations to do this to, try 3x+y=8.

3(4)+y=8.

12+y=8

y=-4.

If you need the answer to be in a point form, it's (4,-4)

heyyy

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752