The larger of two numbers is two more than five times the smaller number. if the sum of the two numbers is 80, find both numbers

x = 41/3

y = 199/3

Step-by-step explanation:

Solve using system of equations

x is smaller number, y is larger

eq1> y + 2 = 5x > y = 5x - 2

eq2> 80 = x + y > y = 80 - x

equate

80 - x = 5x - 2

Solving:

x = 41/3

y = 199/3

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step-by-step explanation:

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb