Determine how many solutions the quadratic fuctionf(x)=x^2-2x+2 has show work

Try this solution:

1. in order to determine solutions it needed to re-write the given equation as x²-2x+2=0 and to solve it.

2. for D=(-2/2)²-1*2= -1; ⇒ D<0, it means this equation has no real solutions. In other words this function has no intersection point with OX-axis.

(x,y) it'll always be like that.

in this case x is grams and y is ounces.

if there were numbers there, like (5,3)

x would be 5 and y would be 3.