Kim and daniel are selling wrapping paper for a school fundraiser. customers can buy rolls of plain wrapping paper and rolls of shiny wrapper paper. kim sold 7 rolls of plain wrapping paper and 8 rolls of shiny wrapping paper for a total of $140. daniel sold 14 rolls of plain wrapping paper and 7 rolls of shiny wrapping paper for a total of $154. find the cost each of one roll of plain wrapping paper and one roll of shiny wrapping paper.

There are two equation:

1) From Kim

2) From Daniel

Let:

x be the cost of rolls of plain wrapping paper

y be the cost of rolls of shiny wrapping paper

Kim:

7x + 8y = 140

Daniel:

14x + 7y = 154

Using elimination method:

(7x + 8y = 140) * -2  (Multiplying the equation by -2)

-14x - 16y = -280

-14x  -16y = -280

14x + 7y = 154

0x - 9y = -126

9y = 126 (Negative sign cancels from both sides)

y = 126 /9

y = 14

The cost of each shiny wrapping paper is $14.

Now solve x, you pick any two equation to solve for x.

7x + 8y = 140

7x + 8(14) = 140 (You know from above y =14)

7x + 112 = 140

7x = 28

x = 28/7

x = 4

The cost of each plain wrapping paper is $4.

Solution: (4,14)

2500

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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