The sum of three consecutive numbers is 414. what is the 2nd number?

 The 2nd number is 138

Step-by-step explanation:

Let x be the  first number, let 2x be the second number and let 3x be the third number

since the sum of the three consecutive numbers is 414, then this implies;

x + 2x + 3x =  414

6x            =    414

To get the value of x, we divide both-side of the equation by six(6)

6x / 6  =  414/6

(On the left-hand side of the equation, the six at the numerator will cancel out the six at the denominator leaving us with just x and the right-hand side of the equation, we will simply divide 414 by 6, that will give us 69)

x    =  69

The first number is x = 69

The second number is 2x = 2×69 =138

The third number is 3x = 3×69 =207

Adding all these numbers up will result to 414.

That is;

69 + 138 + 207 =414

Therefore the 2nd number is 138

throw the computer

step-by-step explanation:

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

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factorizing, we get that:

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then, the solutions are: or

nothing extraneous has been found!