There were 6 women, 4 men, 3 girls, and 5 boys at dinner. in how many ways can 1 woman and 1 man be chosen to set the table?

if you are only counting the adults then 4 times i children to then 10 time

they can be chosen 10 ways since 6 + 4 = 10

Step-by-step explanation:

aloha~! my name is zalgo and i am here to you out on this gracious day. in order to compare the ratios easily, it is best that we simplify the question first. so, the cougars would have 6 wins for 5 losses, bobcats make 2 wins for 1 loss. bulldogs and tigers have a ratio where you can't simplify it. so, the team with the lowest rate would be the bobcats.

i hope that this ! : d

"stay and stay proud! " - zalgo