2y = x + 3 5y = x - 7 what is the solution set of the given system? {(-1/3, -4/3)} {(1/3, 4/3)} {(-29/3, -10/3)} {(29/3, 10/3

{(-29/3, -10/3)}

Step-by-step explanation:

Solve the following system:

{2 y = x + 3 | (equation 1)

{5 y = x - 7 | (equation 2)

Express the system in standard form:

{-x + 2 y = 3 | (equation 1)

{-x + 5 y = -7 | (equation 2)

Subtract equation 1 from equation 2:

{-x + 2 y = 3 | (equation 1)

{0 x+3 y = -10 | (equation 2)

Divide equation 2 by 3:

{-x + 2 y = 3 | (equation 1)

0 x+y = (-10)/3 | (equation 2)

Subtract 2 × (equation 2) from equation 1:

{-x+0 y = 29/3 | (equation 1)

{0 x+y = -10/3 | (equation 2)

Multiply equation 1 by -1:

{x+0 y = (-29)/3 | (equation 1)

{0 x+y = -10/3 | (equation 2)

Collect results:

 {x = -29/3 , y = -10/3

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

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