Using the following diagram: polynomial is 4x^2 + 3x – 7, with 4x^2, 3x, and 7 marked as "terms", 4x^2 marked as the "leading term", and 7 marked as the "constant term", the leading term has the highest degree. the degree of this polynomial is 2. how many solutions does this polynomial have? a. 0 b. 1 c. 2 d. 3

Option C

2 solutions

Explanation:

We have a polynomial of degree 2.  The leading term is having degree 2 and degree is 2.

so this is a quadratic equation, and has 2 solutions.

The solutions are :

Let us complete the square by

= 0

Or [tex](2x+3/4)^2 = 9/16+7  = 121/16

Take square root

2x+3/4 = +11/4 or -11/4

Or 2x= 8/4 or -14/4

x = 1 or x = -7/4

are the two solutions.

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

sorry man i accidentally pressed yes my bad

step-by-step explanation: