1. what's the volume of a right pyramid whose base is a square with a side 6m long and whose altitude is equal to the base side? a. 216m3 b. 72m3 c. 108m3 d. 36m3

I think the answer is B but I don't know for sure.

I think that the formula for finding the volume of a right pyramid is V= 1/3Bh (Volume equals one third base times height).

To find the base we need to take the Length and multiply it by the Width (L x W). Using the information given, we know the the base is a square and that one side of the square is 6. All sides of a square are equal so the length and the with are both 6. Now we multiply 6 (length) by 6 (width) and we get 36. 36 is our base.

We now have to find the height or altitude. In the given information it says that the altitude it equal to the side of the base. The side of the base is 6, so 6 is our altitude.

Now we plug the numbers into our formula.

V= 1/3(36)(6)

Multiply 36 by 6 and we get the answer 216, but we still need to divide it by 1/3. 216 divided by 1/3 equals 72.

Our answer is 72m3

Hope this helps and let me know if I'm wrong.

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

i'm sure goog can you get that answer